Divisibility Applications
Divisibility problems use LCM rules to identify numbers that leave specific remainders when divided by a given set of divisors.
Fundamental Principles
Uniform Remainder Rule
Finding the smallest target number that leaves a uniform remainder 'r' when divided by divisors a, b, and c. The solution follows the format: $\text{Target} = \text{LCM}(a, b, c) + r$.
Constant Difference Remainder Rule
When dividing by a, b, and c leaves different remainders $r_1, r_2, r_3$ but shares a constant difference $k$ such that $(a - r_1) = (b - r_2) = (c - r_3) = k$. The solution format is: $\text{Target} = \text{LCM}(a, b, c) - k$.
Essential Formulation Tips
- Always check if the problem asks for a uniform positive remainder addition or a balanced factor step subtraction.
- When looking for numbers near a specific ceiling limit, scale up your baseline LCM by integer multiples ($2k, 3k$) before processing any remainder math.
Shortcut Execution Techniques
- To find the largest 4-digit number divisible by a set of numbers, divide 9999 by their LCM, find the remainder, and subtract that remainder from 9999.
Contextual Inquiries (FAQs)
Q: Why do we subtract the constant difference 'k' in varying remainder problems?
A: Because subtracting 'k' leaves the target number exactly short of completing the next full division step for each divisor, which generates the required matching remainders.
Example Breakdown: Solving Constant Difference Remainder Layouts
Standard application of constant difference rules.Calculate the differences between the divisors and their remainders: $12 - 9 = 3$ and $16 - 13 = 3$. The common difference is $k = 3$.
Find the baseline LCM of the divisors 12 and 16.
Prime breakdowns: $12 = 2^2 \cdot 3$, $16 = 2^4$. $LCM = 2^4 \cdot 3 = 48$.
Apply the constant difference rule: $\text{Target} = LCM - k$.
Calculate the final value: $\text{Target} = 48 - 3 = 45$.
Divisibility Ceiling and Remainder Configurations
Practice finding numbers that meet specified remainder rules and boundary constraints.
Q1. Find the least number which when divided by 6, 8, and 12 leaves a uniform remainder of 2 in each case.